(x^3/10)-12x=(x^2/5)

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Solution for (x^3/10)-12x=(x^2/5) equation: 


x in (-oo:+oo)

(x^3)/10-(12*x) = (x^2)/5 // - (x^2)/5

(x^3)/10-((x^2)/5)-(12*x) = 0

(x^3)/10-((x^2)/5)-12*x = 0

1/10*x^3-1/5*x^2-12*x = 0

x*(1/10*x^2-1/5*x-12) = 0

1/10*x^2-1/5*x-12 = 0

DELTA = (-1/5)^2-(-12*1/10*4)

DELTA = 121/25

DELTA > 0

x = ((121/25)^(1/2)+1/5)/(1/10*2) or x = (1/5-(121/25)^(1/2))/(1/10*2)

x = 12 or x = -10

x = 0

x = 0

x in { -10, 12, 0 }

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